An explosion blows a rock into three parts. Two parts go off at right angles of each other. These two are 1 kg first part moving with a velocity of 12 ms –1 and 2 kg second part moving with a velocity of 8 ms –1 . If the third part files off with a velocity of 4 ms –1 , its mass would be :
Text Solution
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Apply law of conservation of linear momentum.
Momentum of first part = 1 × 12 = 12 kg ms –1
Momentum of the second part
= 2 × 8 = 16 kg ms –1
∴ Resultant momentum = 
= 20 kg ms –1
The third part should also have the same momentum.
Let the mass of the third part be M, then
4 × M = 20
M = 5 kg.
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